25x^2-8x+1=0

Solution for 25x^2-8x+1=0 equation:

Simplifying
25x2 + -8x + 1 = 0

Reorder the terms:
1 + -8x + 25x2 = 0

Solving
1 + -8x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
0.04 + -0.32x + x2 = 0

Move the constant term to the right:

Add '-0.04' to each side of the equation.
0.04 + -0.32x + -0.04 + x2 = 0 + -0.04

Reorder the terms:
0.04 + -0.04 + -0.32x + x2 = 0 + -0.04

Combine like terms: 0.04 + -0.04 = 0.00
0.00 + -0.32x + x2 = 0 + -0.04
-0.32x + x2 = 0 + -0.04

Combine like terms: 0 + -0.04 = -0.04
-0.32x + x2 = -0.04

The x term is -0.32x.  Take half its coefficient (-0.16).
Square it (0.0256) and add it to both sides.

Add '0.0256' to each side of the equation.
-0.32x + 0.0256 + x2 = -0.04 + 0.0256

Reorder the terms:
0.0256 + -0.32x + x2 = -0.04 + 0.0256

Combine like terms: -0.04 + 0.0256 = -0.0144
0.0256 + -0.32x + x2 = -0.0144

Factor a perfect square on the left side:
(x + -0.16)(x + -0.16) = -0.0144

Can't calculate square root of the right side.

The solution to this equation could not be determined.